How to copy a string using a pointer

Question

Here\'s a program I wrote to copy a string constant.

When the program is run it crashes. Why is this happening ?

#include 

char *alph         


        

Answer 1

cpy function will take two char pointers and the src pointer will point to the initial character of src(char array) defined in the main function, and same as the des pointer will point to the initial location of des(char array) defined in the main function and the while loop value of the src pointer will assign the value to des pointer and increment the pointer to the next element, this will happen until while loop encountered with null and comes out of the loop and des pointer will simply assigned null after taking all the values.

#include
void cpy(char *src,char *des)
{
     while(*(des++) = *(src++));
     *des = '\0';
}

int main()
{
     char src[100];
     char des[100];
     gets(src);
     cpy(src,des);
     printf("%s",des);
}

Output: Image