Convert a List into an Option if it is populated

Question

I have a method that should convert a list to an Option of an object, or None if the list is empty.

def listToOption(myList: List[F         


        

Answer 1

import scalaz._; import Scalaz._
myList.toNel.map(Bar)

toNel - is "to non-empty list" here, it returns Option[NonEmptyList] for safety:

scala> case class Bar(a: NonEmptyList[Int])
defined class Bar

scala> List(1,2,3).toNel.map(Bar)
res64: Option[Bar] = Some(Bar(NonEmptyList(1, 2, 3)))

scala> List[Int]().toNel.map(Bar)
res65: Option[Bar] = None