Currently I am using the PyPDF 2 as a dependency.
I have encountered some encrypted files and handled them as you normally would (in the following code):
<
It has nothing to do with whether the file has been decrypted or not when using the method getNumPages().
If we take a look at the source code of getNumPages():
def getNumPages(self):
"""
Calculates the number of pages in this PDF file.
:return: number of pages
:rtype: int
:raises PdfReadError: if file is encrypted and restrictions prevent
this action.
"""
# Flattened pages will not work on an Encrypted PDF;
# the PDF file's page count is used in this case. Otherwise,
# the original method (flattened page count) is used.
if self.isEncrypted:
try:
self._override_encryption = True
self.decrypt('')
return self.trailer["/Root"]["/Pages"]["/Count"]
except:
raise utils.PdfReadError("File has not been decrypted")
finally:
self._override_encryption = False
else:
if self.flattenedPages == None:
self._flatten()
return len(self.flattenedPages)
we will notice that it is the self.isEncrypted property controlling the flow. And as we all know the isEncrypted property is read-only and not changeable even when the pdf is decrypted.
So, the easy way to handle the situation is just add the password as key-word argument with empty string as default value and pass your password when using the getNumPages() method and any other method build beyond it