numpy array creating with a sequence

Question

I am on my transitional trip from MATLAB to scipy(+numpy)+matplotlib. I keep having issues when implementing some things. I want to create a simple vector array in three dif

Answer 1

if I understand the matlab correctly, you could accomplish something like this using:

a=np.array([0.2]+list(range(1,61))+[60.8])

But there's probably a better way...the list(range(1,61)) could just be range(1,61) if you're using python 2.X.

This works by creating 3 lists and then concatenating them using the + operator.

The reason your original attempt didn't work is because

a=[ [0.2], np.linspace(1,60,60), [60.8] ] creates a list of lists -- in other words:

a[0] == [0.2] #another list (length 1)
a[1] == np.linspace(1,60,60) #an array (length 60)
a[2] == [60.8] #another list (length 1)

The array function expects an iterable that is a sequence, or a sequence of sequences that are the same length.