os.system to invoke an exe which lies in a dir whose name contains whitespace

Question

My code is simply as follows:

file = \'C:\\\\Exe\\\\First Version\\\\filename.exe\'
os.system(file)

When I run this program, a Windows erro

Answer 1

You can use the short name of the file which has spaces in its name.

file = 'C:\\Exe\\FirstV~1\\filename.exe'
os.system(file)