os.system to invoke an exe which lies in a dir whose name contains whitespace

Question

My code is simply as follows:

file = \'C:\\\\Exe\\\\First Version\\\\filename.exe\'
os.system(file)

When I run this program, a Windows erro

Answer 1

Putting quotes around the path will work:

file = 'C:\\Exe\\First Version\\filename.exe'
os.system('"' + file + '"')

but a better solution is to use the subprocess module instead:

import subprocess
file = 'C:\\Exe\\First Version\\filename.exe'
subprocess.call([file])