In my limited experience, I\'ve been on several projects that have had some sort of string utility class with methods to determine if a given string is a number. The idea h
I like code:
public static boolean isIntegerRegex(String str) {
return str.matches("^[0-9]+$");
}
But it will good more when create Pattern before use it:
public static Pattern patternInteger = Pattern.compile("^[0-9]+$");
public static boolean isIntegerRegex(String str) {
return patternInteger.matcher(str).matches();
}
Apply by test we have result:
This operation isIntegerParseInt took 1313 ms.
This operation isIntegerRegex took 1178 ms.
This operation isIntegerRegexNew took 304 ms.
With:
public class IsIntegerPerformanceTest {
private static Pattern pattern = Pattern.compile("^[0-9]+$");
public static boolean isIntegerParseInt(String str) {
try {
Integer.parseInt(str);
return true;
} catch (NumberFormatException nfe) {
}
return false;
}
public static boolean isIntegerRegexNew(String str) {
return pattern.matcher(str).matches();
}
public static boolean isIntegerRegex(String str) {
return str.matches("^[0-9]+$");
}
public static void main(String[] args) {
long starttime, endtime;
int iterations = 1000000;
starttime = System.currentTimeMillis();
for (int i = 0; i < iterations; i++) {
isIntegerParseInt("123");
isIntegerParseInt("not an int");
isIntegerParseInt("-321");
}
endtime = System.currentTimeMillis();
System.out.println("This operation isIntegerParseInt took " + (endtime - starttime) + " ms.");
starttime = System.currentTimeMillis();
for (int i = 0; i < iterations; i++) {
isIntegerRegex("123");
isIntegerRegex("not an int");
isIntegerRegex("-321");
}
endtime = System.currentTimeMillis();
System.out.println("This operation took isIntegerRegex " + (endtime - starttime) + " ms.");
starttime = System.currentTimeMillis();
for (int i = 0; i < iterations; i++) {
isIntegerRegexNew("123");
isIntegerRegexNew("not an int");
isIntegerRegexNew("-321");
}
endtime = System.currentTimeMillis();
System.out.println("This operation took isIntegerRegexNew " + (endtime - starttime) + " ms.");
}
}