Why is `return a or b` a void value expression error in Ruby?

Question

This is just fine:

def foo
  a or b
end

This is also fine:

def foo
  return a || b
end

This returns

Answer 1

return a or b is interpreted as (return a) or b, and so the value of return a is necessary to calculate the value of (return a) or b, but since return never leaves a value in place (because it escapes from that position), it is not designed to return a valid value in the original position. And hence the whole expression is left with (some_void_value) or b, and is stuck. That is what it means.