publishProgress from inside a function in doInBackground?

Question

I use an AsyncTask to perform a long process.

I don\'t want to place my long process code directly inside doInBackground. Instead my long process code is located in

Answer 1

A solution could be placing a simple public class inside the AsyncTask (make sure the task you define is also public) which has a public method that calls publishProgress(val). Passing that class should be available from any other package or class.

public abstract class MyClass {

    public MyClass() {
        // code...
    }

    // more code from your class...

    public class Task extends AsyncTask {
        private Progress progress;

        protected Task() {
            this.progress = new Progress(this);
        }

        // ...

        @Override
        protected Integer doInBackground(String... params) {
            // ...
            SomeClass.doStuff(progress);
            // ...
        }

        // ...

        @Override
        protected void onProgressUpdate(Integer... progress) {
            // your code to update progress
        }

        public class Progress {
            private Task task;

            public Progress(Task task) {
                this.task = task;
            }

            public void publish(int val) {
                task.publishProgress(val);
            }
        }
    }
}

and then in the other class:

public class SomeClass {
    public static void doStuff(Progress progress){
        // do stuff
        progress.publish(20);
        // more stuff etc
    }
}

This worked for me.