Ruby - Keyword Arguments - Can you treat all of the keyword arguments as a hash? How?

Question

I have a method that looks like this:

def method(:name => nil, :color => nil, shoe_size => nil) 
  SomeOtherObject.some_other_method(THE HASH THAT          


        

Answer 1

@Dennis 's answer is useful and educational. However, I noticed that Binding#local_variables will return all the local variables, regardless of when local_variables is executed:

def locals_from_binding(binding_:)
  binding_.local_variables.map { |var|
    [var, binding_.local_variable_get(var)]
  }.to_h
end

def m(a:, b:, c:)
  args = locals_from_binding(binding_: binding)
  pp args

  d = 4
end

m(a: 1, b: 3, c: 5)
# Prints:
#   {:a=>1, :b=>3, :c=>5, :args=>nil, :d=>nil}
# Note the presence of :d

I propose a hybrid solution:

def method_args_from_parameters(binding_:)
  method(caller_locations[0].label)
  .parameters.map(&:last)
  .map { |var|
    [var, binding_.local_variable_get(var)]
  }.to_h
end

def m(a:, b:, c:)
  args = method_args_from_parameters(binding_: binding)
  pp args

  d = 4
end

m(a: 1, b: 3, c: 5)
# Prints:
#   {:a=>1, :b=>3, :c=>5}
# Note the absence of :d