How to generate a random UUID which is reproducible (with a seed) in Python

Question

The uuid4() function of Python\'s module uuid generates a random UUID, and seems to generate a different one every time:

In [1]: import uuid

In          


        

Answer 1

Since the straight-forward solution hasn't been posted yet to generate consistent version 4 UUIDs:

import random
import uuid

rnd = random.Random()
rnd.seed(123)

uuid = uuid.UUID(int=rnd.getrandbits(128), version=4)

where you can see then:

>>> uuid.version
4

This doesn't just "mock" the version information. It creates a proper UUIDv4:

The version argument is optional; if given, the resulting UUID will have its variant and version number set according to RFC 4122, overriding bits in the given hex, bytes, bytes_le, fields, or int.

Python 3.8 docs