Apparently, it is possible to declare a function returning const void:
const void foo()
{
}
g++ seems to consider the co
Not really. But to ignore cv-qualifications on void or to make them errors could create unnecessary complexity in terms of both compiler implementation and end-user code. Consider templates like
template
const T ...
There's no reason to make using void in that scenario a special case (more than it already is), it would just create headaches.
Also, while const void isn't helpful, const void* has its uses.