In normal Python (3.x) we always use showerror() from the tkinter module to display an error message but what should I do in PyQt5 to display exactly the same message type a
All above options didn't work for me using Komodo Edit 11.0. Just had returned "1" or if not implemented "-1073741819".
Usefull for me was: Vanloc's solution.
def my_exception_hook(exctype, value, traceback):
# Print the error and traceback
print(exctype, value, traceback)
# Call the normal Exception hook after
sys._excepthook(exctype, value, traceback)
sys.exit(1)
# Back up the reference to the exceptionhook
sys._excepthook = sys.excepthook
# Set the exception hook to our wrapping function
sys.excepthook = my_exception_hook