Writing to 0xb8000000 yields output on screen without any print statements such as `printf`

Question

#include 
#include 

void main()
{
  char far *v = (char far*)0xb8000000;
  clrscr();

  *v = \'w\';
  v += 2;
  *v = \'e\';

  getch()         


        

Answer 1

First, it gets the address of the beginning of the video buffer. It then clears the screen, and starts adding text to the buffer.