Accept all types as argument in function

Question

How can I in C++ make a function accept every Object, so I can give it numbers, String or other Objects. I am not very well in C++, I hope it\'s not a totally stupid questio

Answer 1

You can use templates for this purpose:

template 
void foo(T const & value)
{
    // value is of some type T, which can be any type at all.
}

What you can actually do with the value may be rather limited without knowing its type -- it depends on the goal of your function. (If someone attempts to call the function with an argument type that causes that function specialization to be ill-formed then your template function will fail to instantiate and it will be a compile-time error.)