3D array C++ using int [] operator

Question

I\'m new to C/C++ and I\'ve been cracking my head but still got no idea how to make an \"structure\" like this

Answer 1

// one-liner
typedef std::vector > > ThreeDimensions;
// expanded
typedef std::vector OneDimension;
typedef std::vector TwoDimensions;
typedef std::vector ThreeDimensions;

(this is tagged c++, after all)

EDIT in response to Joe's question

hello again Joe =) sure. here's the example:

#include 
#include 

int main(int argc, char* const argv[]) {

    /* one-liner */
    typedef std::vector > >ThreeDimensions;
    /* expanded */
    typedef std::vectorOneDimension;
    typedef std::vectorTwoDimensions;
    typedef std::vectorThreeDimensions;

    /*
       create 3 * 10 * 25 array filled with '12'
     */
    const size_t NElements1(25);
    const size_t NElements2(10);
    const size_t NElements3(3);
    const int InitialValueForAllEntries(12);

    ThreeDimensions three_dim(NElements3, TwoDimensions(NElements2, OneDimension(NElements1, InitialValueForAllEntries)));

    /* the easiest way to assign a value is to use the subscript operator */
    three_dim[0][0][0] = 11;
    /* now read the value: */
    std::cout << "It should be 11: " << three_dim[0][0][0] << "\n";
    /* every other value should be 12: */
    std::cout << "It should be 12: " << three_dim[0][1][0] << "\n";

    /* get a reference to a 2d vector: */
    TwoDimensions& two_dim(three_dim[1]);

    /* assignment */
    two_dim[2][4] = -1;
    /* read it: */
    std::cout << "It should be -1: " << two_dim[2][4] << "\n";

    /* get a reference to a 1d vector: */
    OneDimension& one_dim(two_dim[2]);

    /* read it (this is two_dim[2][4], aka three_dim[1][2][4]): */
    std::cout << "It should be -1: " << one_dim[4] << "\n";
    /* you can also use at(size_t): */
    std::cout << "It should be 12: " << one_dim.at(5) << "\n";

    return 0;
}