Why is it allowed to call derived class' private virtual method via pointer of base class?

Question

# include 
using namespace std;

class A
{
    public:
    virtual void f()
    {
        cout << \"A::f()\" << endl;
    }
};
class B:pu         


        

Answer 1

Pretty much like in Java, in C++ you can increase the visibility of methods but not decrease it.