calling template function of template base class [duplicate]

Answer 1

You should do it like this :

template
class derived : public base
{
public:
    void bar()
    {
        base::template foo();
    } 
};

---

Here is full compilable example :

#include 

template
class base
{
public:
    virtual ~base(){}

    template
    void foo()
    {
        std::cout << "base::foo()" << std::endl;
    }
};

template
class derived : public base
{
public:

    void bar()
    {
        base::template foo(); // Compile error
    }
};

int main()
{
  derived< int > a;
  a.bar();
}