Year and week to date in php

Question

I have two pieces of information extracted from a MySQL database, the year(2009, 2010, ect) and the week (1-52). And I need to convert it i

Answer 1

function getStartAndEndDate($week, $year) 
{
    //setting the default time zone
    date_default_timezone_set('America/New_York');

    //getting the
    //$firstWeek = date('W',strtotime("January 1 $year", date(time())));
    //echo "Year : ".$year."
"."Week : ".$week."
";
    $firstWeekThursDay = date('W',strtotime("January $year first thursday",date(time())));

    if($firstWeekThursDay == "01")
    {
        $time      = strtotime("January $year first thursday",date(time()));
        //echo $time."
";
        //echo date('Y-m-d H:i:s',$time)."
";
        $time      = ($time-(4*24*3600))+(((7*$week)-6)*24*3600);
        //echo $time."
";
        //echo date('Y-m-d H:i:s',$time)."
";
        $return[0] = date('Y-m-d', $time);
        $time += 6*24*3600;
        $return[1] = date('Y-m-d', $time);
        //print_r($return);
    }
    else 
    {
        $time = strtotime("January 1 $year", time());
        //echo "
".$time."
";
        //echo date('Y-m-d H:i:s',$time)."
";
        $time      = ($time-(4*24*3600))+(((7*$week)-6)*24*3600);
        //echo $time."
";
        //echo date('Y-m-d H:i:s',$time)."
";
        $return[0] = date('Y-m-d', $time);
        $time     += 6*24*3600;
        $return[1] = date('Y-m-d', $time);
        //print_r($return);
        //echo "
End of Hi
";

    }
    return $return;
}