Determine if angle lies between 2 other angles

Question

I am trying to figure out whether a angle lies between 2 other angles. I have been trying to create a simple function to perform this but none of my techniques will work for

Answer 1

If angle2 were always 0, and angle1 were always between 0 and 180, this would be easy:

return angle1 < 180 && 0 < target && target < angle1;

if I'm reading the requirements correctly.

But it's not that hard to get there.

int reduced1 = (angle1 - angle2 + 360) % 360; // and imagine reduced2 = 0
if (180 < reduced1) { angle2 = angle1; reduced1 = 360 - reduced1; } // swap if backwards
int reducedTarget = (target - angle2 + 360) % 360;
return reduced1 < 180 && 0 < reducedTarget && reducedTarget < reduced1;