using a Bash variable in place of a file as input for an executable

Question

I have an executable that is used in a way such as the following:

executable -v -i inputFile.txt -o outputFile.eps

In order to be more effi

Answer 1

Note: zsh only:

To get a filename containing the contents of ${variable}, use:

<(<<<${variable})

Note:

• <<<${variable} redirects STDIN to come from ${variable}
• <<<${variable} is equivalent to (but faster than) cat <<<${variable}

So for the OP's case:

executable -v -i <(<<<${inputData}) -o outputFile.eps