How can I tell in JavaScript what path separator is used in the OS where the script is running?
Yes all OS's accept CD ../ or CD ..\ or CD .. regardless of how you pass in separators. But what about reading a path back. How would you know if its say, a 'windows' path, with ' ' and \ allowed.
What happens when you depend on, for example, the installation directory %PROGRAM_FILES% (x86)\Notepad++. Take the following example.
var fs = require('fs'); // file system module
var targetDir = 'C:\Program Files (x86)\Notepad++'; // target installer dir
// read all files in the directory
fs.readdir(targetDir, function(err, files) {
if(!err){
for(var i = 0; i < files.length; ++i){
var currFile = files[i];
console.log(currFile);
// ex output: 'C:\Program Files (x86)\Notepad++\notepad++.exe'
// attempt to print the parent directory of currFile
var fileDir = getDir(currFile);
console.log(fileDir);
// output is empty string, ''...what!?
}
}
});
function getDir(filePath){
if(filePath !== '' && filePath != null){
// this will fail on Windows, and work on Others
return filePath.substring(0, filePath.lastIndexOf('/') + 1);
}
}
targetDir is being set to a substring between the indices 0, and 0 (indexOf('/') is -1 in C:\Program Files\Notepad\Notepad++.exe), resulting in the empty string.
This includes code from the following post: How do I determine the current operating system with Node.js
myGlobals = { isWin: false, isOsX:false, isNix:false };
Server side detection of OS.
// this var could likely a global or available to all parts of your app
if(/^win/.test(process.platform)) { myGlobals.isWin=true; }
else if(process.platform === 'darwin'){ myGlobals.isOsX=true; }
else if(process.platform === 'linux') { myGlobals.isNix=true; }
Browser side detection of OS
var appVer = navigator.appVersion;
if (appVer.indexOf("Win")!=-1) myGlobals.isWin = true;
else if (appVer.indexOf("Mac")!=-1) myGlobals.isOsX = true;
else if (appVer.indexOf("X11")!=-1) myGlobals.isNix = true;
else if (appVer.indexOf("Linux")!=-1) myGlobals.isNix = true;
Helper Function to get the separator
function getPathSeparator(){
if(myGlobals.isWin){
return '\\';
}
else if(myGlobals.isOsx || myGlobals.isNix){
return '/';
}
// default to *nix system.
return '/';
}
// modifying our getDir method from above...
Helper function to get the parent directory (cross platform)
function getDir(filePath){
if(filePath !== '' && filePath != null){
// this will fail on Windows, and work on Others
return filePath.substring(0, filePath.lastIndexOf(getPathSeparator()) + 1);
}
}
getDir() must be intelligent enough to know which its looking for.
You can get even really slick and check for both if the user is inputting a path via command line, etc.
// in the body of getDir() ...
var sepIndex = filePath.lastIndexOf('/');
if(sepIndex == -1){
sepIndex = filePath.lastIndexOf('\\');
}
// include the trailing separator
return filePath.substring(0, sepIndex+1);
You can also use 'path' module and path.sep as stated above, if you want to load a module to do this simple of a task. Personally, i think it sufficient to just check the information from the process that is already available to you.
var path = require('path');
var fileSep = path.sep; // returns '\\' on windows, '/' on *nix