Get data using await async without try catch

Question

I am trying to use await-async without try-catch for this:

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Answer 1

If you have such above single line async/await function, then this would have been clean code for you:

const getUsers = async (time, shouldReject=false) => {
    return new Promise((resolve, reject) => {
      setTimeout(() => {
        if (shouldReject) {
          reject(Error('Rejected...'));
        } else {
          resolve(["User1", "User2"]);
        }
      }, time);
    });
}

const userOperation = users => {
  console.log("Operating user", users);
}

// Example 1, pass
getUsers(100)
    .then(users => userOperation(users))
    .catch(e => console.log(e.message));

// Example 2, rejected
getUsers(100, true)
    .then(users => userOperation(users))
    .catch(e => console.log(e.message));

And for multiple await in a single async function, it would good to have try/catch block as below:

const users = async () => {
    try {
        const value = await getUsers(1000, false);
        const value1 = await getUsers2(1000, false);
        ...
    } catch (error) {
        ...
    }
}