Decorator for overloading in Python

Question

I know it\'s not Pythonic to write functions that care about the type of the arguments, but there are cases when it\'s simply impossible to ignore types because they are han

Answer 1

This doesn't directly answer your question, but if you really want to have something that behaves like an overloaded function for different types and (quite rightly) don't want to use isinstance then I'd suggest something like:

def func(int_val=None, str_val=None):
    if sum(x != None for x in (int_val, str_val)) != 1:
        #raise exception - exactly one value should be passed in
    if int_val is not None:
        print('This is an int')
    if str_val is not None:
        print('This is a string')

In use the intent is obvious, and it doesn't even require the different options to have different types:

func(int_val=3)
func(str_val="squirrel")