JavaScript curry function

Question

I have implemented a curry function this way:

function curry (fn) {
    var slice = Array.prototype.slice,
        args = slice.apply(arguments,         


        

Answer 1

You're missing a return in your curry function.

I.e.

return function () {
    return fn.apply(null, args.concat(slice.apply(arguments)));
};

That seems to work :)