Reverse a list in haskell

Question

I am trying to reverse a list.

Following is my code:

reverseList :: [Int] -> [Int]
reverseList [] = []
reverseList (x:xs) =  x:reverseList xs
         


        

Answer 1

Simple; use the built-in reverse function:

print (reverse [1,2,3,4,5]) -- [5,4,3,2,1]