Obtaining $group result with group count

Question

Assuming I have a collection called \"posts\" (in reality it is a more complex collection, posts is too simple) with the following structure:

> db.posts.f         


        

Answer 1

I'm not sure you need the aggregation framework for this other than counting all the tags eg:

db.posts.aggregate(
  { "unwind" : "$tags" },
  { "group" : {
      _id: { tag: "$tags" },
      count: { $sum: 1 }
  } }
);

For paginating through per tag you can just use the normal query syntax - like so:

db.posts.find({tags: "RANDOM"}).skip(10).limit(10)