Say I have something like this:
new File(\"test\").eachFile() { file->
println file.getName()
}
This prints the full filename of eve
Note
import java.io.File;
def fileNames = [ "/a/b.c/first.txt",
"/b/c/second",
"c:\\a\\b.c\\third...",
"c:\\a\b\\c\\.text"
]
def fileSeparator = "";
fileNames.each {
// You can keep the below code outside of this loop. Since my example
// contains both windows and unix file structure, I am doing this inside the loop.
fileSeparator= "\\" + File.separator;
if (!it.contains(File.separator)) {
fileSeparator = "\\/"
}
println "File extension is : ${it.find(/((?<=\.)[^\.${fileSeparator}]+)$/)}"
it = it.replaceAll(/(\.([^\.${fileSeparator}]+)?)$/,"")
println "Filename is ${it}"
}
Some of the below solutions (except the one using apache library) doesn't work for this example - c:/test.me/firstfile
If I try to find an extension for above entry, I will get ".me/firstfile" - :(
Better approach will be to find the last occurrence of File.separator if present and then look for filename or extension.
Note: (There is a little trick happens below. For Windows, the file separator is \. But this is a special character in regular expression and so when we use a variable containing the File.separator in the regular expression, I have to escape it. That is why I do this:
def fileSeparator= "\\" + File.separator;
Hope it makes sense :)
Try this out:
import java.io.File;
String strFilename = "C:\\first.1\\second.txt";
// Few other flavors
// strFilename = "/dd/ffffdd/2.dd/dio/dkljlds.dd"
def fileSeparator= "\\" + File.separator;
if (!strFilename.contains(File.separator)) {
fileSeparator = "\\/"
}
def fileExtension = "";
(strFilename =~ /((?<=\.)[^\.${fileSeparator}]+)$/).each { match, extension -> fileExtension = extension }
println "Extension is:$fileExtension"