Comma operator returns first value instead of second in argument list?

Question

MDN claims that:

The comma operator evaluates both of its operands (from left to right) and returns the value of the second operand

Answer 1

When you use it like that, the comma is not an operator, it's a separator between the parameters in the call to the alert method.

If you put parentheses around them so that it's an expression, it will show you 2:

alert( (1,2) );