Parsing shell script arguments

Question

$myscript.sh -host blah -user blah -pass blah

I want to pass arguments into it.

I\'m used to doing $1, $2,

Answer 1

Here is a simple way to handle both long and short options:

while [[ $1 == -* ]]; do
    case "$1" in
      -h|--help|-\?) show_help; exit 0;;
      -v|--verbose) verbose=1; shift;;
      -f) if (($# > 1)); then
            output_file=$2; shift 2
          else 
            echo "-f requires an argument" 1>&2
            exit 1
          fi ;;
      --) shift; break;;
      -*) echo "invalid option: $1" 1>&2; show_help; exit 1;;
    esac
done

From How can I handle command-line arguments (options) to my script easily?