Sed : print all lines after match

Question

I got my research result after using sed :

zcat file* | sed -e \'s/.*text=\\(.*\\)status=[^/]*/\\1/\' | cut -f 1 - | grep \"pattern\"
         


        

Answer 1

zcat file* | sed -e 's/.*text=\(.*\)status=[^/]*/\1/' | ***cut -f 1 - | grep "pattern"***

instead change the last 2 segments of your pipeline so that:

zcat file* | sed -e 's/.*text=\(.*\)status=[^/]*/\1/' | **awk '$1 ~ "pattern" {print $0}'**