Getting base name of the source file at compile time

Question

I\'m using GCC; __FILE__ returns the current source file\'s entire path and name: /path/to/file.cpp. Is there a way to get just the file\'s name file.cpp<

Answer 1

Since you tagged CMake, here's a neat solution to add to your CMakeLists.txt: (copied from http://www.cmake.org/pipermail/cmake/2011-December/048281.html ). (Note : some compilers don't support per-file COMPILE_DEFINITIONS ! but it works with gcc)

set(SRCS a/a.cpp b/b.cpp c/c.cpp d/d.cpp)

foreach(f IN LISTS SRCS)
 get_filename_component(b ${f} NAME)
 set_source_files_properties(${f} PROPERTIES
  COMPILE_DEFINITIONS "MYSRCNAME=${b}")
endforeach()

add_executable(foo ${SRCS})

Note : For my application I needed to escape the filename string like this:

COMPILE_DEFINITIONS "MYSRCNAME=\"${b}\"")