Get the error code from tweepy exception instance

Question

I\'m new to python and I\'m trying to use a library. It raises an exception, and I am trying to identify which one. This is what I am trying:

except tweepy.T         


        

Answer 1

To get just the error code use the method monq posted. The following example illustrates how to get both the error code and the message. I had to extract the message from the e.reason string, if anyone has a better method to retrieve just the message, please share.

Note: This code should work for any error code/reason with the following format.

[{'code': 50, 'message': 'User not found.'}]

def getExceptionMessage(msg):
    words = msg.split(' ')

    errorMsg = ""
    for index, word in enumerate(words):
        if index not in [0,1,2]:
            errorMsg = errorMsg + ' ' + word
    errorMsg = errorMsg.rstrip("\'}]")
    errorMsg = errorMsg.lstrip(" \'")

    return errorMsg

And you can call it like so:

try:
    # Some tweepy api call, ex) api.get_user(screen_name = usrScreenName)
except tweepy.TweepError as e:
    print (e.api_code)
    print (getExceptionMessage(e.reason))