Point-free in Haskell

Question

I have this code that I want to make point-free;

(\\k t -> chr $ a + flip mod 26 (ord k + ord t -2*a))

How do I do that?

Also are the

Answer 1

Connect on IRC, #haskell, and ask lambdabot !:

 @pl (\k t -> chr $ a + flip mod 26 (ord k + ord t -2*a))
 [the answer]