How to Initialize char array from a string

Question

I want to do the following

char a[] = { \'A\', \'B\', \'C\', \'D\'};

But I do not want to write these characters separately. I want somethi

Answer 1

The compilation problem only occurs for me (gcc 4.3, ubuntu 8.10) if the three variables are global. The problem is that C doesn't work like a script languages, so you cannot take for granted that the initialization of u and t occur after the one of s. That's why you get a compilation error. Now, you cannot initialize t and y they way you did it before, that's why you will need a char*. The code that do the work is the following:

#include 
#include 

#define STR "ABCD"

const char s[] = STR;
char* t;
char* u;

void init(){
    t = malloc(sizeof(STR)-1);
    t[0] = s[0];
    t[1] = s[1];
    t[2] = s[2];
    t[3] = s[3];


    u = malloc(sizeof(STR)-1);
    u[0] = s[3];
    u[1] = s[2];
    u[2] = s[1];
    u[3] = s[0];
}

int main(void) {
    init();
    puts(t);
    puts(u);

    return EXIT_SUCCESS;
}