UNIX Programming. struct timeval how to print it (C-programming)

Question

I am trying to print a value of type timeval. Actually I am able to print it, but I get the following warning:

Multiple markers at this line

• format ‘%l

Answer 1

Since struct timeval will be declared something like:

struct timeval {
    time_t      tv_sec;
    suseconds_t tv_usec;
}

you need to get at the underlying fields:

printf ("%ld.%06ld\n", usage.ru_stime.tv_sec, usage.ru_stime.tv_usec);
printf ("%ld.%06ld\n", usage.ru_utime.tv_sec, usage.ru_utime.tv_usec);