Access arguments to Bash script inside a function [duplicate]

Answer 1

Thanks for the tips - they inspired me to write a callstack function. I used the 'column' command for esthetics.

callstack() {
    local j=0 k prog=$(basename $0)
    for ((i=1; ((i<${#BASH_ARGC[*]})); i++))
    do
        echo -n "${FUNCNAME[$i]/main/$prog} " # function name
        args=""
        for ((k=0; ((k<${BASH_ARGC[$i]})); k++))
        do
            args="${BASH_ARGV[$j]} $args" # arguments
            let j++
        done
        echo -e "$args\t|${BASH_LINENO[$i]}" $(sed -n ${BASH_LINENO[$i]}p "$0" 2>/dev/null) # line calling the function
    done | column -t -s $'\t' -o ' ' | sed 1d # delete callstack entry
}

compareTemplates brother_001270_1.jpg     |163  compareTemplates "$f" # process the rest
processPdf brother_001270.pdf             |233  filetype "${f%[*}" pdf && processPdf "$f"
process brother_001270.pdf                |371  --process) shift; process "$@"; exit ;; # process jpg or pdf
sm --quiet --process brother_001270.pdf   |0