How does defer and named return value work?

Question

I just started learning Go and I got confused with one example about using defer to change named return value in the The Go Blog - Defer, Panic, and Recover.

The exam

Answer 1

I think the confusion is about function in function how about if you classified like this:

  func main() {
      fmt.Println(c()) //the result is 5
  }

  // the c function returned value is named j
  func c() (j int)  {
      defer changei(&j)
      return 6
  }
  func changei(j *int) {
      //now j is 6 because it was assigned by return statement 
      // and if i change guess what?! i changed the returned value
      *j--;
  }

but if the return value is not named like this:

  func main() {
      fmt.Println(c()) //the result will become 6
  }

  // the c function returned value is not named at this time
  func c() int  {
      j := 1
      defer changei(&j)
      return 6
  }
  func changei(j *int) {
      //now j = 1
      // and if i change guess what?! it will not effects the returned value
      *j--;
  }

I hope this will clear the confusion and that is how i did happy Go coding