Default assignment operator= in c++ is a shallow copy?

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挽巷 2020-12-14 05:42

Just a simple quick question which I couldn\'t find a solid answer to anywhere else. Is the default operator= just a shallow copy of all the class\' members on the right ha

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萌比男神i (楼主)

2020-12-14 06:41

As illustrated by the code snippet below, the = (assignment) operator for STL performs a deep copy.

#include 
#include 
#include 
#include 

using namespace std;

int main(int argc, const char * argv[]) {
    /* performs deep copy */
    map  > m;
    stack  s1;
    stack  s2;

    s1.push(10);
    cout<<&s1<<" "<<&(s1.top())<<" "< > mp;
    stack  s1p;
    stack  s2p;

    s1p.push(new int);
    cout<<&s1p<<" "<<&(s1p.top())<<" "< v1,v2;
    vector v1p, v2p;

    v1.push_back(1);
    cout<<&v1<<" "<<&v1[0]<<" "<