Django order_by() filter with distinct()

Question

How can I make an order_by like this ....

p = Product.objects.filter(vendornumber=\'403516006\')\\
                   .order_by(\'-created\').di         


        

Answer 1

In case you are hoping to use a separate field for distinct and order by another field you can use the below code

from django.db.models import Subquery

Model.objects.filter(
    pk__in=Subquery(
       Model.objects.all().distinct('foo').values('pk')
    )
).order_by('bar')