Proper way to use iloc in Pandas

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故里飘歌
故里飘歌 2020-12-14 04:39

I have the following dataframe df:

print(df)

    Food         Taste
0   Apple        NaN
1   Banana       NaN
2   Candy        NaN
3   Milk         NaN
4            


        
4条回答
  •  [愿得一人]
    2020-12-14 05:32

    .iloc uses integer location, whereas .loc uses name. Both options also take both row AND column identifiers (for DataFrames). Your inital code didn't work because you didn't specify within the .iloc call which column you're selecting. The second code line you tried didn't work because you mixed integer location with column name, and .iloc only accepts integer location. If you don't know the column integer location, you can use Index.get_loc in place as suggested above. Otherwise, use the integer position, in this case 1.

    df.iloc[0:2, df.columns.get_loc('Taste')] = 'good'
    df.iloc[2:6, df.columns.get_loc('Taste')] = 'bad'
    

    is equal to:

    df.iloc[0:2, 1] = 'good'
    df.iloc[2:6, 1] = 'bad'
    

    in this particular situation.

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