How to copy char *str to char c[] in C?

Question

Trying to copy a char *str to char c[] but getting segmentation fault or invalid initializer error.

Why is this code is giving me a

Answer 1

char c[] must have some size;

for example

char c[]= "example init string";

// that set up table c to c[19]; You can allocate it directly at the begginign of Your program;

char c[19] = {0}; // null filled table

char c[i] is the pointer so You don't need to copy anything; char c[19] ; c = "example init string"; // now &c[0] points the same address;

Copy can be done wiht

 strcpy(dst, src);

but MS force You to use secure function:

strcpy_s(dst,buffsize,src);