How to copy char *str to char c[] in C?

Question

Trying to copy a char *str to char c[] but getting segmentation fault or invalid initializer error.

Why is this code is giving me a

Answer 1

use strncpy to be sure to not copy more charachters than the char[] can contains

char *s = "abcdef";
char c[6];

strncpy(c, s, sizeof(c)-1);
// strncpy is not adding a \0 at the end of the string after copying it so you need to add it by yourself
c[sizeof(c)-1] = '\0';

Edit: Code added to question

Viewing your code the segmentation fault could be by the line

strcpy(c, token)

The problem is if token length is bigger than c length then memory is filled out of the c var and that cause troubles.