How to remove surrogate characters in Java?

Question

I am facing a situation where i get Surrogate characters in text that i am saving to MySql 5.1. As the UTF-16 is not supported in this, I want to remove these surrogate pai

Answer 1

Here's a couple things:

• Character.isSurrogate(char c):

  A char value is a surrogate code unit if and only if it is either a low-surrogate code unit or a high-surrogate code unit.

• Checking for pairs seems pointless, why not just remove all surrogates?

• x == false is equivalent to !x

• StringBuilder is better in cases where you don't need synchronization (like a variable that never leaves local scope).

I suggest this:

public static String removeSurrogates(String query) {
    StringBuilder sb = new StringBuilder();
    for (int i = 0; i < query.length(); i++) {
        char c = query.charAt(i);
        // !isSurrogate(c) in Java 7
        if (!(Character.isHighSurrogate(c) || Character.isLowSurrogate(c))) {
            sb.append(firstChar);
        }
    }
    return sb.toString();
}

Breaking down the if statement

You asked about this statement:

if (!(Character.isHighSurrogate(c) || Character.isLowSurrogate(c))) {
    sb.append(firstChar);
}

One way to understand it is to break each operation into its own function, so you can see that the combination does what you'd expect:

static boolean isSurrogate(char c) {
    return Character.isHighSurrogate(c) || Character.isLowSurrogate(c);
}

static boolean isNotSurrogate(char c) {
    return !isSurrogate(c);
}

...

if (isNotSurrogate(c)) {
    sb.append(firstChar);
}