How can I make XHR.onreadystatechange return its result?

Question

I\'m new to JavaScript programming. I\'m now working on my Google Chrome Extension. This is the code that doesn\'t work... :P

I want getURLInfo function

Answer 1

You are dealing with an asynchronous function call here. Results are handled when they arrive, not when the function finishes running.

That's what callback functions are for. They are invoked when a result is available.

function get(url, callback) {
    var xhr = new XMLHttpRequest();
    xhr.open("GET", url, true);
    xhr.onreadystatechange = function () {
        if (xhr.readyState == 4) {
            // defensive check
            if (typeof callback === "function") {
                // apply() sets the meaning of "this" in the callback
                callback.apply(xhr);
            }
        }
    };
    xhr.send();
}
// ----------------------------------------------------------------------------


var param = "http://example.com/";                  /* do NOT use escape() */
var finalUrl = "http://RESTfulAPI/info.json?url=" + encodeURIComponent(param);

// get() completes immediately...
get(finalUrl,
    // ...however, this callback is invoked AFTER the response arrives
    function () {
        // "this" is the XHR object here!
        var resp  = JSON.parse(this.responseText);

        // now do something with resp
        alert(resp);
    }
);

Notes:

• escape() has been deprecated since forever. Don not use it, it does not work correctly. Use encodeURIComponent().
• You could make the send() call synchronous, by setting the async parameter of open() to false. This would result in your UI freezing while the request runs, and you don't want that.
• There are many libraries that have been designed to make Ajax requests easy and versatile. I suggest using one of them.