how do access previous item in list using linQ?

Question

I have:

List A  = new List(){1,2,3,4,5,6};

List m=new List();
for(int i=1;i

        

Answer 1

Well, a straightforward translation would be:

var m = Enumerable.Range(1, A.Count - 1)
                  .Select(i => A[i] + A[i - 1])
                  .ToList();

But also consider:

var m = A.Skip(1)
         .Zip(A, (curr, prev) => curr + prev)
         .ToList();

Or using Jon Skeet's extension here:

var m = A.SelectWithPrevious((prev, curr) => prev + curr)
         .ToList();

But as Jason Evans points out in a comment, this doesn't help all that much with readability or brevity, considering your existing code is perfectly understandable (and short) and you want to materialize all of the results into a list anyway.

There's nothing really wrong with:

var sumsOfConsecutives = new List();

for(int i = 1; i < A.Count; i++)
   sumsOfConsecutives.Add(A[i] + A[i - 1]);