C++11 variadic std::function parameter

Question

A function named test takes std::function<> as its parameter.

template
void test(std::functio         


        

Answer 1

It looks like you want to use overloading

template
void test(R f(A...))
{
    test(std::function(f));
}

This simple implementation will accept most if not all the functions you will try to pass. Exotic functions will be rejected (like void(int...)). More work will give you more genericity.