Arrays passed by reference by default?

Question

I\'m reading a C++ book which says this:

C++ passes arrays to functions by reference—the called functions can modify the element values in the callers

Answer 1

To summarise my comment, you are absolutely right!

The book is wrong in its choice of jargon. It tries to talk about arrays decaying to C pointers. It refers to passing this pointer by value as passing by reference which is WRONG.

This is a common enough misconception, I believe I was taught this way as well (passing pointer as value == passing by reference). This is completely wrong in terms of C++ references and pass by reference.

If this were correct, I wouldn't be able to do this..

void ModifyMyArray(int *array){
   int oops[4]= {0};
   array = oops;

   array[2] = 1;
}
...
int MyArray[4] = {1,3,5,7};

ModifyMyArray(MyArray);

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