I always thought the complexity of:
1 + 2 + 3 + ... + n is O(n), and summing two n by n matrices would be O(n^2).
But today I read from a textbo
There's a difference between summing N arbitrary integers and summing N that are all in a row. For 1+2+3+4+...+N, you can take advantage of the fact that they can be divided into pairs with a common sum, e.g. 1+N = 2+(N-1) = 3+(N-2) = ... = N + 1. So that's N+1, N/2 times. (If there's an odd number, one of them will be unpaired, but with a little effort you can see that the same formula holds in that case.)
That is not O(N^2), though. It's just a formula that uses N^2, actually O(1). O(N^2) would mean (roughly) that the number of steps to calculate it grows like N^2, for large N. In this case, the number of steps is the same regardless of N.