Cycle a list from alternating sides

Question

Given a list

a = [0,1,2,3,4,5,6,7,8,9]

how can I get

b = [0,9,1,8,2,7,3,6,4,5]

That is, produce a new lis

Answer 1

Two versions not seen yet:

b = list(sum(zip(a, a[::-1]), ())[:len(a)])

and

import itertools as it

b = [a[j] for j in it.accumulate(i*(-1)**i for i in range(len(a)))]